Answer:
0.13J/g°C
Explanation:
Given parameters:
Mass = 345g
Initial temperature = 45°C
Final temperature = 72°C
Quantity of heat = 1215J
Unknown:
Specific heat of lead = ?
Solution:
To solve this problem, we use the expression below:
H = mass x specific heat capacity x (Final - initial temperature)
Now insert the parameters and solve;
1215 = 345 x Specific heat x (72 - 45)
1215 = 9315 x specific heat
Specific heat = 0.13J/g°C
