Mass of CCl₄ = 1004.137 g
Further explanation
Given
3.93 x 10²⁴ molecules of CCl₄
Required
mass
Solution
1 mol = 6.02 x 10²³ particles(molecules, ions, atoms)
So mol of CCl₄ :
n = N : No(No = Avogadro's number)
n = 3.93 x 10²⁴ : 6.02 x 10²³
n = 6.528
Mass of CCl₄ (MW=153,82 g/mol) :
mass = mol x MW
mass = 6.528 x 153,82 g/mol
mass = 1004.137 g
