Answer: [tex]y=\dfrac15 x +1[/tex]
Step-by-step explanation:
Since argument is the value of independent variable x .
Here y= 1 when x = 0.
[tex]\dfrac{dy}{dx}=\dfrac15[/tex]
[tex]\Rightarrow\ dy=\dfrac15 dx[/tex]
Taking integration on both sides , we get
[tex]\int dy = \dfrac15 \int dx\\\\\Rightarrow\ y= \dfrac15 x +c[/tex]
Put y=1 and x=0 [given] , then
[tex]1= 0+c\\\\\Rightarrow\ c=1[/tex]
Hence, the function will be
[tex]y=\dfrac15 x +1[/tex]
