The amount of 600 gram remaining after 3 half-lives is 75 g.
The half life of a substance is given by:
[tex]N=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ N\ is\ substance\ remaining\ after\ t\ years,N_o\ is\ the \ original\ sample\\t_\frac{1}{2}\ is\ the\ half\ life\\\\\\Given\ that:\\N_o=600\ g, t=3t_\frac{1}{2} , hence:\\\\N=600(\frac{1}{2} )^\frac{3t_\frac{1}{2} }{t_\frac{1}{2} } \\\\N=600(\frac{1}{2} )^3=75\ g[/tex]
The amount of 600 gram remaining after 3 half-lives is 75 g.
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