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A U-shaped tube with both arms open to the air has a 55.0 cm column of liquid of unknown density in its right arm. Beneath this liquid and not mixing with it is glycerin that extends into the left arm of the tube. The surface of the glycerin in the left arm is 18.0 cm below the surface of the unknown liquid in the right arm. What is the density of the unknown liquid?

Respuesta :

nuhulawal20

Answer: the density of the unknown liquid is 0.8485 g/cm³

Explanation:

Given the data in the question;

from pascal's Law;  δ_liuid × g × h_liquid = δ_glycerin × g × h_glycerin

so

δ_liuid × 55.0 = δ_glycerine × ( 55.0 - 18.0)

we know that density of glycerin is 1.2613 gram per cubic centimeter

so

δ_liquid × 55.0 = 1.2613 × 37

δ_liquid  = (1.2613 × 37) / 55.0

δ_liquid = 46.6681 / 55.0

δ_liquid = 0.8485 g/cm³

Therefore the density of the unknown liquid is 0.8485 g/cm³

adefioyelaoye

The density of the unknown liquid is 0.8485 g/cm³

We can get the density using Pascal's Law

 density of liquid × g × height of liquid = density of glycerin × g × height of glycerin

density of liquid × 55.0 =  density of glycerine × ( 55.0 - 18.0)

Density of glycerin = 1.2613 g/cm³

density of liquid × 55.0 = 1.2613 × 37

density of liquid  = (1.2613 × 37) / 55.0

                            = 46.6681 / 55.0

                            = 0.8485 g/cm³

Density of the unknown liquid = 0.8485 g/cm³

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