Answer:
[tex]Q=0.350J[/tex]
Explanation:
Hello!
In this case, since the equation that allows us to compute the energy required for such temperature increase is:
[tex]Q=mC(T_2-T_1)[/tex]
Whereas m is the mass, C the specific heat and T2 and T1 the final and initial temperature respectively; thus, by plugging in the given data, we obtain the following energy with consistent units and significant figures:
[tex]Q=541.0mg*\frac{1g}{1000mg}0.139\frac{J}{g\°C} (16.06\°C-11.4\°C)\\\\Q=0.350J[/tex]
Considering that the specific heat can be used by unit of °C or K because their difference is equivalent.
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