Answer:
Work done during lifting up body is 0
Explanation:
From the question it is given that
Distance traveled by body during lifting is 2 m
since work done by body is given by
work done W = F x s x cosθ
Where F= mg = weight of body
s= distance traveled = 2m
θ = angle between force and distance vector
here θ = 90° as body is lifting up
on substituting the respected values we get
⇒ W = mg x 2 x cos90° = 0 {∵ cos90°= 0 }
Thus, work done during lifting up body is 0
