Answer:
3980.89 ohms
Explanation:
The capacitive reactance is expressed as;
[tex]X_c = \frac{1}{2 \pi fC}[/tex]
f is the frequency
C is the capacitance of the capacitor
Given
f = 60H
C = C1+C2 (parallel connection)
C = 15μF + 25μF
C = 40μF
C = [tex]40 * 10^{-6}F[/tex]
Substitute into the formula:
[tex]X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89[/tex]
Hence the total capacitive reactance is 3980.89 ohms
