Answer:
The equation of the line joining the points (-1,-1), (1,-1) is
y +1 =0
Step-by-step explanation:
Step(i):-
Given curve y = 2 x² -3 , x = -1 and x=1
substitute x =-1 in given curve y = 2 x² -3
y = 2 (-1 )² - 3
y = 2 -3
y = - 1
First point A( -1 ,-1)
substitute x =1 in given curve y = 2 x² -3
y = 2 (1)² - 3
y = -1
Second point B( 1 , -1 )
Step(ii):-
A( -1, -1 ) and B( 1,-1)
slope of the line
[tex]m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{-1-(-1)}{1-(-1)} =0[/tex]
The equation of the straight line passing through the point ( -1,-1 ) having slope m =0
y - y₁ = m ( x - x₁ )
y - (-1) = 0( x-(-1)
y +1 =0
The equation of the line joining the points (-1,-1), (1,-1) is y +1 =0
