Respuesta :
Answer:
Explanation:
Given elements:
Sodium
Fluorine
The ion Na⁺ is made up of 10 electrons, its electronic configuration is:
1s² 2s² 2p⁶
Ion F⁻ is made up of 10 electrons, its electronic configuration is:
1s² 2s² 2p⁶
These ions do not form +2 because they cannot attain stability by losing or gaining two electrons.
Sodium atom is made up of one valence electron. If it loses one electron, it will be isoelectronic with Neon.
Fluorine has 7 valence electrons, to attain stability, it must gain one electron to form an octet. This way it will be isoelectronic with Neon.
Losing or gaining two electrons will not make the elements attain stability.
The electron configuration for;
- Sodium ion, Na+ = 1s² 2s² 2p⁶
- Flourine ion, Cl- = 1s² 2s² 2p⁶
- Both atoms don't form 2+ and 2- ions respectively because, they do not attain stability in such manner.
First, we must understand stand that atoms of elements ionize to become ions in such a manner as to become electronically stable.
In essence, the aim of ionization is to attain the closest state of electronic stability.
- The electron configuration of Na atom is 1s² 2s² 2p⁶ 3s¹ which becomes 1s² 2s² 2p⁶ upon ionization by loss of its valent electron to Na+.
- The electron configuration of Cl atom is 1s² 2s² 2p⁵ which becomes 1s² 2s² 2p⁶ upon ionization by gain of an electron to Cl-.
Both atoms consequently become isolectronic with Neon, Ne.
Additionally, the two elements, Sodium and Flourine don't form 2+ and 2- ions respectively because, they do not attain electronic stability in such manner.
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