Answer:
The acceleration of the object is 314.57 m/[tex]s^{2}[/tex].
Explanation:
From Newton's second law of motion,
F = ma
where: F is the force applied on an object, m is the mass of the object and a is the acceleration of the object.
⇒ a = [tex]\frac{F}{m}[/tex]
In the given question, the resultant force, F should be determined.
Total horizontal force, [tex]F_{x}[/tex] = 16 - 126
= -110 N
The horizontal force applied to the object is 110 N to the left.
Vertical force, [tex]F_{y}[/tex] = 4 N.
Resultant force, F = [tex]\sqrt{F_{x} ^{2} + F_{y} ^{2} }[/tex]
= [tex]\sqrt{(-110)^{2} + (4)^{2} }[/tex]
= [tex]\sqrt{12116}[/tex]
= 110.0727
Resultant force, F = 110.1 N
So that,
a = [tex]\frac{110.1}{0.35}[/tex]
= 314.5714
a = 314.57 m/[tex]s^{2}[/tex]
The acceleration of the object is 314.57 m/[tex]s^{2}[/tex].
