Answer:
The price of a sandwich is £2.5 and the price of a croissant is £2
Step-by-step explanation:
Let s be the number of sandwiches and c be the number of croissants
Then according to given statements the equations will be:
[tex]2s+3c = 11\ \ \ \ \ \ \ Eqn\ 1\\3s+6c =19.50\ \ \ Eqn\ 2[/tex]
Multiplying equation 1 by 2 and subtracting equation 2 from the new equation
[tex]2(2s+3c) = 11*2\\4s+6c = 22[/tex]
Now
[tex]4s+6c-(3s+6c) = 22-19.50\\4s+6c-3s-6c = 2.5\\s = 2.5[/tex]
Putting s=2.5 in equation 1
[tex]2(2.5)+3c = 11\\5+3c = 11\\3c = 11-5\\3c = 6\\\frac{3c}{3} = \frac{6}{3}\\c = 2[/tex]
Hence,
The price of a sandwich is £2.5 and the price of a croissant is £2
