Given:
Coordinates of point A are (7,3).
Point B is on the x-axis whose abscissa is 11.
To find:
The distance between A and B.
Solution:
Point B is on the x-axis whose abscissa is 11. So, x-coordinate of the point B is 11 and y-coordinate is 0. It means, coordinates of point B are (11,0).
The distance between A(7,3) and B(11,0) is
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]D=\sqrt{(11-7)^2+(0-3)^2}[/tex]
[tex]D=\sqrt{(4)^2+(-3)^2}[/tex]
[tex]D=\sqrt{16+9}[/tex]
[tex]D=\sqrt{25}[/tex]
[tex]D=5[/tex]
Therefore, the distance between point A and B is 5 units.
