Which expression is equivalent to : (2n - 3)?
icre
0-1
2n - 1
n-3
2n - 3
cred
Please help me!
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Answer: Choice C) [tex]\frac{8}{9}n - 1\frac{1}{3}[/tex]
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Explanation:
We multiply the outer term 4/9 with each term inside
The improper fraction 4/3 converts to the mixed number 1 & 1/3
4/3 = (3+1)/3 = 3/3 + 1/3 = 1 + 1/3 = 1 & 1/3
So overall, we can say [tex]\frac{4}{9}(2n-3) = \frac{8}{9}n - 1\frac{1}{3}[/tex]
This is equivalent to saying [tex]\frac{4}{9}(2n-3) = \frac{8}{9}n - \frac{4}{3}[/tex]