Answer:
k = 52.2 N / m
Explanation:
For this exercise we are going to use the conservation of mechanical energy.
Starting point. When it is 30 m high
Em₀ = K + U = ½ m v² + m g h
Final point. Right when you hit the water
[tex]Em_{f}[/tex] = K_{e} = ½ k x²
in this case the distance the bungee is stretched is 30 m
x = h
as they indicate that there are no losses, energy is conserved
Em₀ = Em_{f}
½ m v² + m g h = ½ k h²
k = [tex]\frac{m (v^{2} + 2 g h)}{h^{2} }[/tex]
let's calculate
k = [tex]\frac{75 \ ( 20^{2} + 2 \ 9.8 \ 30)}{30^{2} }[/tex]
k = 52.2 N / m
