Answer:
1.69 g Na₂O
General Formulas and Concepts:
Chemistry - Atomic Structure
Explanation:
Step 1: Define
0.0273 mol Na₂O
Step 2: Identify Conversions
Molar Mass of Na - 22.99 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol
Step 3: Convert
[tex]0.0273 \ mol \ Na_2O(\frac{61.98 \ g \ Na_2O}{1 \ mol \ Na_2O} )[/tex] = 1.69205 g Na₂O
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
1.69205 g Na₂O ≈ 1.69 g Na₂O
