Answer:
The velocity [tex]v = 1989.2 \ m/s[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 0.500 \ m[/tex]
The maximum transverse speed is [tex]v = 4.0 \ m/s[/tex]
The maximum transverse acceleration is [tex]a = 1.00 *10^{5} \ m/s^2[/tex]
Generally the frequency of the wave is mathematically represented as
[tex]f = \frac{w}{2 \pi }[/tex]
Here w is the angular speed which is mathematically evaluated as
[tex]w = \frac{a}{v}[/tex]
=> [tex]w = \frac{1.00 *10^{5}}{4}[/tex]
=> [tex]w = 25000 \ rad/sec[/tex]
So
[tex]f = \frac{ 25000 }{2 * 3.142 }[/tex]
=> [tex]f = \frac{ 25000 }{2 * 3.142 }[/tex]
=> [tex]f = 3978.4 \ Hz[/tex]
Gnerally the propagation speed of the wave is mathematically represented as
[tex]v = f * \lambda[/tex]
=> [tex]v = 3978.4 * 0.500[/tex]
=> [tex]v = 1989.2 \ m/s[/tex]
