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A police car is moving to the left at 34m/sec while its siren is emitting a 600Hz tone. What tone would you hear if you were parked along side the road

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boffeemadrid

Answer:

[tex]545.89\ \text{Hz}[/tex]

Explanation:

[tex]v_o[/tex] = Velocity of observer = 0

[tex]v_s[/tex] = Velocity of source = 34 m/s

v = Speed of sound in air = 343 m/s

f = Emitted frequency = 600 Hz

Doppler effect will be observed

[tex]f_o=f(\dfrac{v+v_o}{v+v_s})\\\Rightarrow f_o=600(\dfrac{343+0}{343+34})\\\Rightarrow f_o=545.89\ \text{Hz}[/tex]

The frequency heard will be [tex]545.89\ \text{Hz}[/tex].

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