Answer:
t = 3.52 s
Explanation:
Given that,
The deceleration of a car is, a = -1.7 m/s²
The initial velocity of the car, u = 15 m/s
Final velocity of the car, v = 9 m/s
We need to find the time that is required to slow the car from 15 m/s to 9 m/s. The definition of acceleration is :
[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{9-15}{-1.7}\\\\t=3.52\ s[/tex]
So, it will take 3.52 seconds to slow the car from 15 m/s to 9 m/s.
