In a population of 100 four o’clock plants, there are 50 red-flowered plants with genotype CRCR, 30 pink-flowered plants with genotype CRCW, and 20 white-flowered plants with genotype CWCW. Match the correct frequencies for the following alleles and genotypes.a. CRCR (Click to select) 0.3 0.65 0.35 0.2 0.4 0.25 0.5 b. CRCW (Click to select) 0.2 0.25 0.5 0.65 0.3 0.4 0.35 c. CWCW (Click to select) 0.5 0.3 0.2 0.25 0.35 0.4 0.65 d. CR (Click to select) 0.65 0.2 0.5 0.4 0.3 0.25 0.35 e. CW (Click to select) 0.65 0.3 0.35 0.4 0.5 0.25 0.2

Alleles are the variant form of the gene, which is present on the same locus of the chromosomes. The alleles code for different traits.

The frequencies of the four o'clock plant is:

a) CRCR frequency = 0.5

b) CRCW frequency = 0.3

c) CWCW frequency = 0.2

d) CR frequency = 0.65

e) CW frequency = 0.35

Given that:

Total number of individuals = 100

Number of red-flowered plants = 50 (CRCR)

Number of pink-flowered plants = 30 (CRCW)

Number of white-flowered plants = 20 (CWCW)

Now, to calculate the frequency , let us divide the genotypic frequency with the total number of individuals:

Frequency of CRCR = [tex]\dfrac {50}{100}[/tex] = 0.5

Frequency of CRCW = [tex]\dfrac {30}{100}[/tex] = 0.3

Frequency of CWCW = [tex]\dfrac {20}{100}[/tex] = 0.2

Now, the number of alleleic frequncy in a population, the sum of genotypic purebred frequency tothe half of heterozygous frequency, such that:

f (CR) = F (CRCR) + [tex]\dfrac{1}{2}[/tex] F (CRCW) = 0.5 + 0.3 x [tex]\dfrac{1}{2}[/tex] = 0.65

f (CW) = F (CWCW) + [tex]\dfrac{1}{2}[/tex] F (CRCW) = 0.2 + 0.3 x [tex]\dfrac{1}{2}[/tex] = 0.35

Thus, the allelic frequency for red and white are 0.65 and 0.35, respectively.

To know more about allelic frequency, refer to the following link:

https://brainly.com/question/14309065