Answer: The resultant pressure is 3.22 atm
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex] (At constant volume and number of moles)
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 2.79 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]T_1[/tex] = initial temperature of gas = 273K
[tex]T_2[/tex] = final temperature of gas = 315 K
[tex]\frac{2.79}{273}=\frac{P_2}{315}[/tex]
[tex]P_2=3.22atm[/tex]
Thus the resultant pressure is 3.22 atm
