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Answer:

There are 0.1387 moles of oxygen atoms.

Explanation:

First we calculate how many moles of ammonium phosphate there are:

  • There are 3 nitrogen moles per (NH₄)₃PO₄ mole.
  • There are 0.104 nitrogen moles
  • Thus there are (0.104 mol N * [tex]\frac{1mol(NH_4)_3PO_4}{3molN}[/tex]) 0.0347 moles of (NH₄)₃PO₄.

Finally we calculate how many moles of oxygen atoms are there in 0.312 moles of (NH₄)₃PO₄:

  • There are 4 oxygen moles per (NH₄)₃PO₄ mole.
  • There are 0.0347 moles of (NH₄)₃PO₄.

Thus there are (0.0347 mol (NH₄)₃PO₄ * [tex]\frac{4molO}{1mol(NH_4)_3PO_4}[/tex] ) 0.1387 moles of O.

Eduard22sly

The number of moles of oxygen atoms in the sample is 0.1388 mole

We'll begin by calculating the number of mole of (NH₄)₃PO₄ that contains 0.104 mole of N. This can be obtained as follow:

3 moles of N is present in 1 mole of (NH₄)₃PO₄.

Therefore,

0.104 mole of N will be present in = 0.104 / 3 = 0.0347 mole of (NH₄)₃PO₄.

  • Finally, we shall determine the number of oxygen atoms in the sample

1 mole of (NH₄)₃PO₄ contains 4 mole of O.

Therefore,

0.0347 mole of (NH₄)₃PO₄ will contain = 0.0347 × 4 = 0.1388 mole of O

Thus, the number of moles of oxygen atoms in the sample is 0.1388 mole.

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