Answer:
Explanation:
Given;
output power of the incandescent lightbulb , P = 120 W
input voltage, V = 200 V
The resistance of the filament is calculated as;
[tex]P = \frac{V^2}{R}[/tex]
Where;
R is the resistance of the filament
[tex]R = \frac{V^2}{P} \\\\R = \frac{200^2}{120} \\\\R = 333.33 \ ohms[/tex]
The rms current is given as;
[tex]P = I_{rms} V_{rms}\\\\I_{rms} = \frac{P}{V_{rms}} \\\\I_{rms} =\frac{120}{200}\\\\ I_{rms} = 0.6 \ A[/tex]