Answer:
0.445
Explanation:
In friction, the coefficient of friction formula is expressed as;
[tex]\mu = \frac{F_f}{R}[/tex]
Ff is the frictional force = Wsinθ
R is the reaction = Wcosθ
Substitute inti the equation;
[tex]\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta[/tex]
Given
θ = 24°
[tex]\mu = tan 24^0\\\mu = 0.445\\[/tex]
Hence the coefficient of kinetic friction between the box and the ramp is 0.445
