Answer:
The range of [tex]f\circ g \,(x) = 2^{x+1}[/tex] is [tex]Ran\{f\circ g\,(x)\} = (0, +\infty)[/tex].
Step-by-step explanation:
Let [tex]f\circ g \,(x) = 2^{x+1}[/tex], [tex]\forall\, x \in \mathbb{R}[/tex]. The graphic represents a power function, whose lower bound is the horizontal asymptote [tex]y=0[/tex]. From the graphic we find the range of the composite function corresponds to the values of the function associated with the vertical axis (y-axis).
Hence, the range of [tex]f\circ g \,(x) = 2^{x+1}[/tex] is [tex]Ran\{f\circ g\,(x)\} = (0, +\infty)[/tex].
