Answer:
10000 g BaNO₃
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
3.02 × 10²⁵ formulas units BaNO₃
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Ba - 137.33 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of BaNO₃ - 137.33 + 14.01 + 3(16.00) = 199.34 g/mol
Step 3: Convert
[tex]3.02 \cdot 10^{25} \ formula \ units \ BaNO_3(\frac{1 \ mol \ BaNO_3}{6.022 \cdot 10^{23} \ formula \ units \ BaNO_3} )(\frac{199.34 \ g \ BaNO_3}{1 \ mol \ BaNO_3} )[/tex] = 9996.79 g BaNO₃
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
9996.79 g BaNO₃ ≈ 10000 g BaNO₃
