Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the cart accelerates at 5 m/s^2. What is the friction force resisting the pull?
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Answer:
0.5 N
Explanation:
(0.6 kg)(9.8 m/s^2) = 5.88 N
(0.6 kg)(5 m/s^2) = 3 N
4 N - 3 N = 1 N
1 N/5.88 N = 0.17
(0.17)(3 N) = 0.51 N which rounds to 0.5 N