Answer:
0.0917 mol Co(CrO₄)₃
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
37.3 g Co(CrO₄)₃
Step 2: Identify Conversions
Molar Mass of Co - 58.93 g/mol
Molar Mass of Cr - 52.00 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol
Step 3: Convert
[tex]37.3 \ g \ Co(CrO_4)_3(\frac{1 \ mol \ Co(CrO_4)_3}{406.93 \ g \ Co(CrO_4)_3} )[/tex] = 0.091662 mol Co(CrO₄)₃
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃
