Answer:
[tex]a=51.77\ m/s^2[/tex]
Explanation:
Given that,
The mass of a toy, m = 0.62 kg
Force with which a child pull the toy = 16.3 N
The force with which the toy pulled in the opposite direction = -15.8 N
We need to find the acceleration of the toy. Let F be the net force acting on the toy. It is equal to :
F = 16.3 N - (-15.8 N)
= 32.1 N
Let a be the acceleration of the toy. Using Newton' second law of motion to find it.
F = ma
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{32.1}{0.62}\\\\a=51.77\ m/s^2[/tex]
So, the acceleration of the toy is [tex]51.77\ m/s^2[/tex].
