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What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm? Use P V equals n R T. and R equals 0.0821 StartFraction L times atmospheres over moles time K EndFraction.. 2.95 K 5.24 K 138 K 246 K

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Answer:

D on Edge2021

Explanation:

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shristiparmar1221

The temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm will be 245.9K. Hence, Option (D) i.e, 246 K  is correct. It can be solved with the help of Ideal gas equation.

What is Ideal gas equation ?

The ideal gas equation is formulated as: PV = nRT.

In the above equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

Given ,

  • p =  2.21 atm
  • V = 6850 ml (=6.85 L)
  • n = 0.750 mol
  • R = 0.0821 atmL/mol K

From,

PV=nRT

T = (2.21×6.85) ÷ (0.750×0.0821)

T = 245.9K  i.e,  246 K approx

Therefore, The temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm will be 245.9K. Hence, Option (D) i.e, 246 K  is correct.

Learn more about Ideal gas here ,

https://brainly.com/question/8711877

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