An election for favorite lunch snack is between Apples, Beets, and Carrots. Students voted for their top three from best to least. The results are: ABC : 41 BAC : 26 CAB : 42 How many votes will A have in total after B is eliminated due to the Hare method

Respuesta :

Answer: after eliminating B due to Hare Method, A will have a total of 67 VOTES

Step-by-step explanation:

Given that;

The results are

ABC : 41

BAC : 26

CAB : 42

NOW

A>B>C = 41 ⇒ A has 41 votes

B>A>C = 26 ⇒ B has 26 votes

C>A>B = 42 ⇒ C has 42 votes

According to Hare method, least votes gainers will be eliminated and once eliminated, his/her/its votes will be transferred to the next choice of person/thing.

based on the question; B will be eliminated

so we have;

A>B>C = 41 ⇒ A has 41 votes

B>A>C = 26 ⇒ B has 26 votes

we eliminate B, the votes are transferred to the next (A)

A>C = 26 ⇒ A has 26 votes

C>A>B = 42 ⇒ C has 42 votes

SO in total

A votes = 41 + 26 = 67 VOTES

Therefore after eliminating B due to Hare Method, A will have a total of 67 VOTES

After eliminating B due to Hare Method, A will have a total of 67 votes

We have given that,the results are

ABC : 41

BAC : 26

CAB : 42

A>B>C = 41 ⇒ A has 41 votes

B>A>C = 26 ⇒ B has 26 votes

C>A>B = 42 ⇒ C has 42 votes

What is the Hare method?

The Hare method is least votes gainers will be eliminated and once eliminated,The  votes will be transferred to the next choice of person/thing.

From the given question we have B will be eliminated

Therefore  we have

A>B>C = 41 ⇒ A has 41 votes

B>A>C = 26 ⇒ B has 26 votes

We eliminate B, the votes are transferred to the next (A)

A>C = 26 ⇒ A has 26 votes

C>A>B = 42 ⇒ C has 42 votes

Therefore the total votes are

A votes = 41 + 26 = 67 votes

Therefore after eliminating B due to Hare Method, A will have a total of 67 votes.

To learn more about the votes visit:

https://brainly.com/question/3710029