Answer: Yes we can extract all the lithium from the amount of compound we have.
Explanation:
To calculate the moles :
[tex]moles=\frac{\text {given mass}}{\text {Molar mass}}[/tex]
[tex]\text{Moles of} Li=\frac{150g}{7g/mol}=21.4moles[/tex]
[tex]\text{Moles of} Li_2O=\frac{675g}{30g/mol}=22.5moles[/tex]
[tex]2Li_2O\rightarrow 4Li+O_2[/tex]
According to stoichiometry :
2 moles of [tex]Li_2O[/tex] produce 4 moles of [tex]Li[/tex]
Thus 22.5 moles of [tex]Li_2O[/tex] will produce=[tex]\frac{4}{2}\times 22.5=45moles[/tex] of Li
As 21.4 moles is a lesser quantity than 45 moles, thus it can be produced
Yes, you can extract all the lithium you need from the compound
We'll begin by calculating the mass of lithium, Li in 1 mole of Li₂O. This can be obtained as described below:
1 mole of Li₂O = (2×7) + 16
1 mole of Li₂O = 14 + 16 = 30 g
SUMMARY
30 g of Li₂O contains 14 g of Li.
30 g of Li₂O contains 14 g of Li.
Therefore,
675 g of Li₂O Will contain = (675 × 14)/30 = 315 g of Li.
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