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Using the rule-of-1 approach, what is the proportional change in centripetal acceleration, ac, for an object in a circular path when the tangential velocity is doubled? 2ac (doubles) 2 A sub c, (doubles) ac2 (halves) the fraction with numerator A sub c and denominator 2, (halves) ac4 (quarters) the fraction with numerator A sub c and denominator 4, (quarters) 4ac (quadruples)

Respuesta :

Answer:

4ac (quadruples)

Explanation:

The general formula for centripetal acceleration is given as follows:

[tex]a_{c} = \frac{v^2}{r}\\\\[/tex]   -------------- equation (1)

where,

ac = centripetal acceleration

v = tangential speed

r = radius of circular path

Now, if we double tangential speed, v' = 2v, then the acceleration will become:

[tex]a_{c}' = \frac{(2v)^2}{r}\\\\a_{c}' = \frac{4v^2}{r}[/tex]

using equation (1):

[tex]a_{c}' = 4a_{c}[/tex]

therefore, the correct answer is:

4ac (quadruples)