Answer:
The equation [tex]x^2 + 6x -5 = 4x^2[/tex] have 2 non-real solution, 2 imaginary solutions.
Step-by-step explanation:
Using the Discriminant to find the number and type of solutions to [tex]x^2 + 6x -5 = 4x^2\\x^2-4x^2+6x-5=0\\-3x^2+6x-5=0[/tex]
The discriminant is: [tex]b^2-4ac[/tex]
We have a = -3, b=6 and c=-5
Putting values and finding discriminant
[tex]b^2-4ac\\=(6)^2-4(-3)(-5)\\=36-60\\=-24\\[/tex]
So, we get discriminant = -24
if discriminant < 0 the solution will have two non-real imaginary solutions.
In our case discriminant < 0 i,e discriminant = -24
So, The equation [tex]x^2 + 6x -5 = 4x^2[/tex] have 2 non-real solution, 2 imaginary solutions.
