Answer:
[tex]\frac{10a + 6}{-a^2 + 1}[/tex] is undefined at a = 1
Step-by-step explanation:
Required
Which is undefined at a = 1
An expression is undefined when its denonimator equals 0.
So, we have to test the denominator of each.
(A): 7a + 7
This gives:
[tex]= 7(1) + 7[/tex]
[tex]= 7 + 7[/tex]
[tex]= 14[/tex]
(B): 5a - 10
This gives:
[tex]= 5(1) - 10[/tex]
[tex]= 5- 10[/tex]
[tex]= -5[/tex]
(C) -a² + 1
This gives
[tex]-(1^2) + 1[/tex]
[tex]= -1 + 1[/tex]
[tex]=0[/tex]
(D) 3a²
This gives:
[tex]= 3(1)^2[/tex]
[tex]= 3 * 1[/tex]
[tex]= 3[/tex]
Notice that only (C) equals 0.
Hence:
[tex]\frac{10a + 6}{-a^2 + 1}[/tex] is undefined at a = 1
