Given that,
Weight of a car, W = 12,000 N
It is parked on a 36° slope.
To find,
The acceleration of the car.
Solution,
Let m be the mass of the car. Using formula for weight of an object.
W = mg
[tex]m=\dfrac{12000}{9.8}\\\\=1224.48\ kg[/tex]
Let a be the acceleration of the car. Using second law of motion as follows :
[tex]a=\dfrac{F_{\text{parallel}}}{m}\\\\=\dfrac{F\sin\theta}{m}\\\\=\dfrac{12000\times \sin(36)}{1224.48}\\\\=5.76\ m/s^2[/tex]
So, the acceleration of the car is [tex]5.76\ m/s^2[/tex].
