Answer:
The probability, to the nearest 10th of a percent, that both marbles drawn will be red is 28.5%
Step-by-step explanation:
Number of red marbles = 4
Number of blue marbles = 8
Number of Green marbles = 2
Total number of marbles = 4+8+2 =14
We need to find the probability, to the nearest 10th of a percent, that both marbles drawn will be red?
The formula used will be: [tex]Probability=\frac{Number\:of\:favourable\:outcomes}{Number\:of\;possible\:outcomes}\\[/tex]
In our case, Number of favourable outcomes = 4 (as red marbles are drawn)
Number of possible outcome = 14 (Total number of marbles)
The probability will be:
[tex]Probability=\frac{Number\:of\:favourable\:outcomes}{Number\:of\;possible\:outcomes}\\\\Probability=\frac{4}{14}\\ Probability=0.2857\\[/tex]
Now, calculating nearest 10th of a percent
[tex]Probability = 0.2857*100\\Probability=28.5%[/tex]
So, the probability, to the nearest 10th of a percent, that both marbles drawn will be red is 28.5%
