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3. Decomposition of a sample of KCIO3(s) produced 25.2 mL of 020, at a temperature of
27°C and a pressure of 89.6 kPa. What is the volume, in ml, of this oxygen gas at 45°C
and a pressure of 89.6 kPa ?

Respuesta :

ardni313

The volume of Oxygen gas=26.712 ml

Further explanation

The pressure constant = 89.6 kPa, so we use Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

V₁=25.2 ml

T₁=27+273=300 K

T₂=45+273=318 K

[tex]\tt V_2=\dfrac{V_1\times T_2}{T_1}\\\\V_2=\dfrac{25.2\times 318}{300}\\\\V_2=26.712~ml[/tex]

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