Calculate the molarity of the two solutions.
The first solution contains 0.350 mol of NaOH in 1.05 L of solution.
molarity:

The second solution contains 14.3 g of NaCl in 879 mL of solution.
molarity:

Respuesta :

1. 0.33 M

2. 0.278 M

Further explanation

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

1. 0.350 mol of NaOH in 1.05 L of solution.

n=0.35

V=1.05 L

Molarity :

[tex]\tt M=\dfrac{0.35}{1.05}=0.33[/tex]

2. 14.3 g of NaCl in 879 mL of solution.

mol NaCl(MW=58.5 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{14.3~g}{58.5~g/mol}=0.244[/tex]

Molarity :

[tex]\tt M=\dfrac{0.244}{0.879~L}\\\\M=0.278[/tex]