• When volleyballs are purchased, they are not fully inflated. A partially inflated
volleyball can be modeled by a sphere whose volume is approximately 180 in). After
being fully inflated, its volume is approximately 294 in. To the nearest tenth of an
inch, how much does the radius increase when the volleyball is fully inflated?

Respuesta :

Answer:

The radius increase when the volleyball is fully inflated is 0.5

Step-by-step explanation:

Volume of Partially inflated volleyball = 180 in³

Volume of Full inflated volleyball = 294 in³

We need to find how much does the radius increase when the volleyball is fully inflated?

First we will find the radius of both Partially inflated and Full inflated volleyball. Then we will find increase in radius.

The formula for Volume of sphere is: [tex]Volume=\frac{4}{3}\pi r^3[/tex]

Finding Radius of Partially inflated volleyball

Volume = 180

Putting values and finding radius of Partially inflated volleyball

[tex]Volume=\frac{4}{3}\pi r^3\\180=\frac{4}{3}*3.14*r^3\\4.186r^3=180\\r^3=\frac{180}{4.186}\\r^3=43.0\\Taking\:cube\:root\:on\:both\:sides\\\sqrt[3]{r^3}=\sqrt[3]{47}\\r= 3.6[/tex]

So, radius of Partially inflated volleyball is r = 3.6

Finding Radius of Fully inflated volleyball

Volume = 294

Putting values and finding radius of Fully inflated volleyball

[tex]Volume=\frac{4}{3}\pi r^3\\294=\frac{4}{3}*3.14*r^3\\4.186\:r^3=294\\r^3=\frac{294}{4.186}\\r^3=70.23\\Taking\:cube\:root\:on\:both\:sides\\\sqrt[3]{r^3}=\sqrt[3]{70.23}\\r= 4.1[/tex]

So, radius of Partially inflated volleyball is r = 4.1

Now, finding increase in radius by subtracting radius of fully inflated volleyball with partially inflated volleyball

Increase in radius of Fully inflated volleyball = 4.1 - 3.6

Increase in radius of Fully inflated volleyball = 0.5

So, the radius increase when the volleyball is fully inflated is 0.5