[tex]2(i+3)>4(1-i)[/tex]
Distribute 2 in (i+3) and 4 in (1-i)
[tex]2i+6>4-4i[/tex]
Move -4i to another side and 6 to another side. When moving to another side, you'll have to change the sign/operator to opposite (Plus -> Minus, Multiply -> Divide)
[tex]2i+4i>4-6\\6i>-2\\[/tex]
For this part, move 6 to divide -2.
[tex]i>\frac{-2}{6} \\i>\frac{-1}{3}\\i>-\frac{1}{3}[/tex]
Whenever either a numerator or a denominator is in negative, we can pull out the negative in the middle of fraction.
Note that i is the symbol of imaginary number - as defined - i = √-1 But for this one, It's just a variable if I assume.
Thus, the answer is i > -1/3
