Answer:
a. 754cm³ (3 s.f.)
b. 415cm² (3 s.f.)
Step-by-step explanation:
Formulas (for easier reference):
Volume of cone: [tex]\pi[/tex]r²[tex]\frac{h}{3}[/tex]
Volume of hemisphere: [tex]\frac{2}{3}[/tex][tex]\pi[/tex]r³
Surface area of cone without base: [tex]\pi[/tex]rl
Surface area of hemisphere without base: 2[tex]\pi[/tex]r²
We can just apply the formulas for the question:
Volume of toy = ([tex]\pi[/tex] × 6² × [tex]\frac{8}{3}[/tex]) + ([tex]\frac{2}{3}[/tex] × [tex]\pi[/tex] 6³)
= 96[tex]\pi[/tex] + 144[tex]\pi[/tex]
= 240[tex]\pi[/tex]
= 754cm³ (3 s.f.)
Surface area of toy = ([tex]\pi[/tex] × 6 × 10) + (2 × [tex]\pi[/tex] × 6²)
= 60[tex]\pi[/tex] + 72[tex]\pi[/tex]
= 132[tex]\pi[/tex]
= 415cm² (3 s.f.)
