Given:
Triangle ABC is similar to triangle EFG.
Pentagon ABCDE is similar to pentagon QRSTU.
To find:
The length of segment FG.
The missing value in [tex]\dfrac{D}{EA}=\dfrac{?}{UQ}[/tex].
Solution:
In card A,
AC = 15 in.
BC = 9 in.
EG = 10 in.
Triangle ABC is similar to triangle EFG. So, the corresponding sides are proportional.
[tex]\dfrac{AC}{BC}=\dfrac{EG}{FG}[/tex]
Putting the values, we get
[tex]\dfrac{15}{9}=\dfrac{10}{FG}[/tex]
[tex]\dfrac{5}{3}=\dfrac{10}{FG}[/tex]
[tex]5\times FG=3\times 10[/tex]
[tex]5FG=30[/tex]
Divide both sides by 5.
[tex]FG=6[/tex]
Therefore, the length of segment FG is 6 in.
In card B, pentagon ABCDE is similar to pentagon QRSTU.
The corresponding sides of similar figure are proportional. So,
[tex]\dfrac{AB}{QR}=\dfrac{BC}{RS}=\dfrac{CD}{ST}=\dfrac{DE}{TU}=\dfrac{EA}{UQ}[/tex]
Now,
[tex]\dfrac{CD}{ST}=\dfrac{EA}{UQ}[/tex]
It can be written as
[tex]\dfrac{CD}{EA}=\dfrac{ST}{UQ}[/tex]
Therefore, the missing side is ST.
