Given that,
The radius of a flywheel, r = 20 cm = 0.2 m
The centripetal acceleration experienced on the edge of the flywheel = 900 cm/s² = 9 m/s²
To find,
The speed of a point on the edge.
Solution,
The formula for the centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{9\times 0.2} \\\\=1.34\ m/s[/tex]
Hence, the required speed is 1.34 m/s
The speed of a point on the edge of the flywheel is 134.16cm/s
The formula for calculating the centripetal acceleration of the flywheel is expressed as:
[tex]a=\frac{v^2}{r}[/tex]
where;
v is the speed of the flywheel
r is the radius of the wheel
Given the following parameters
r = 20.0cm
a = 900cm/s²
Substituting the given parameters into the formula above;
[tex]900=\frac{v^2}{20}\\v^2=900\times 20\\v^2=18,000\\v=\sqrt{18,000}\\v= 134.16cm/s[/tex]
Hence the speed of a point on the edge of the flywheel is 134.16cm/s
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