Answer:
[tex]x<-6[/tex]
Step-by-step explanation:
[tex]3x-2>5x+10[/tex]
Add 2 to both sides
[tex]3x-2+2>5x+10+2[/tex]
Simplify
[tex]3x>5x+12[/tex]
Subtract [tex]5x[/tex] from both sides
[tex]3x-5x>5x+12-5x[/tex]
Simplify
[tex]-2x>12[/tex]
Multiply both sides by [tex]-1[/tex] (reverse the inequality)
[tex](-2x)(-1)<12(-1)[/tex]
Simplify
[tex]2x<-12[/tex]
Divide both sides by [tex]2[/tex]
[tex]\frac{2x}{2} <\frac{-12}{2}[/tex]
Divide the numbers: [tex]\frac{2}{2} =1[/tex]
[tex]=x[/tex]
Divide the numbers: [tex]\frac{-12}{2}[/tex]
Apply fraction rule: [tex]\frac{-a}{b} =-\frac{a}{b}[/tex]
[tex]=\frac{12}{2}[/tex]
Divide the numbers: [tex]\frac{12}{2} =6[/tex]
[tex]=-6[/tex]
[tex]x<-6[/tex]
