Answer:
The length and width of the rectangle are: [tex]\mathbf{2x^5y^8\:and\: 12xy^7}[/tex]
Option A is correct.
Step-by-step explanation:
We are given: [tex]Area\:of\:rectangle=Length\times Width[/tex]
if [tex]Area = 24x^6y^{15}[/tex]we need to find the length and width of rectangle from options given.
Looking at the options, Option B,C and D are incorrect because multiplying the given lengths and widths, the area is not equal to [tex]24x^6y^{15}[/tex]
Only Option A gives us the result i,e
[tex]Area=2x^5y^8\times 12xy^7\\Area=24x^6y^{15}[/tex]
So, the length and width of the rectangle are: [tex]\mathbf{2x^5y^8\:and\: 12xy^7}[/tex]
Option A is correct.
