Answer:
The equation of the line will be:
Step-by-step explanation:
Given the points
Finding the slope
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(3,\:0\right)[/tex]
[tex]m=\frac{0-0}{3-0}[/tex]
[tex]m=0[/tex]
We know that the value of y-intercept can be obtained by setting x=0, and solving for y
Here,
at x = 0, the value of y = 0
Thus,
y-intercept = b = 0
We know the slope-intercept form of the line equation is
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept
now substituting m = 0 and b = 0 in the slope-intercept form
y = mx+b
y = 0(x) + (0)
y = 0+0
y = 0
Therefore, the equation of line will be:
