The empirical formula of the compound having 57.5% Na, 40.0% O, and 2.5% H is NaOH (Option C)
Data obtained from the question
- Na = 57.5%
- O = 40%
- H = 2.5%
- Empirical formula =?
How to determine the empirical formula
Divide by their molar mass
Na = 57.5 / 23 = 2.5
O = 40 / 16 = 2.5
H = 2.5 / 1 = 2.6
Divide by the smallest
Na = 2.5 / 2.5 = 1
O = 2.5 / 2.5 = 1
H = 2.5 / 2.5 = 1
Thus, the empirical formula of the compound is NaOH
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