Respuesta :
Answer:
4 and 7
Step-by-step explanation:
There are probably several ways to do this but this is how I did it:
First, I listed all the number combinations, that added together equaled 11.
This is what it looked like:
1, 10
2, 9
3, 8
4, 7
5, 6
6, 5
7, 4
I stopped here since the next step would be to double the first number and 8*2 would already be more than 15.
Then, I doubled the first number and added the second number to it, when I saw that didn't equal 15, I eliminated that possibility and moved on to the next set of numbers. When I reached 4, 7 I saw that 4*2 equaled 8 and 8 plus 7 equals 15 so I had the answer.
There are probably much more efficient ways to do this but this is how I did it.
Hope it helped!
The first number is 4 and second number is 7.
Let us consider that first number is x and second number is y.
[tex]2x+y=15\\\\x+y=11[/tex]
Substitute [tex]y=11 - x[/tex]in equation [tex]2x+y=15[/tex]
[tex]2x+11-x=15\\\\x=15-11=4[/tex]
So, [tex]y=11-x=11-4=7[/tex]
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