The mass of FeS formed : 11.97 g
Further explanation
Reaction
Fe(s) + S(s) → FeS(s)
mass Fe=7.62 g
mol Fe(MW=56 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{7.62}{56}\\\\mol=0.136[/tex]
mass S=8.67 g
mol S(MW=32 g/mol) :
[tex]\tt mol=\dfrac{8.67}{32}=0.271[/tex]
Limiting reactant : smaller ratio(mol:coefficient) ⇒coefficient=1
Fe : S =0.136 : 0.271⇒Fe limiting(smaller), S excess
Mol FeS based on Fe , so mol FeS=0.136
Mass FeS(MW=88 g/mol) :
[tex]\tt mass=mol\times MW\\\\mass=0.136\times 88=11.97~g[/tex]
